A concave mirror produces three times magnified real image of an object placed at 10 cm in front of it. Where is image located?
Class = 8th [ICSE]
Chapter = Light
Points = 10
Answers
Answered by
1
Solve.) Here given,
Magnification m = -3 (real image)
Object-distance u = -10 cm (object on the left)
Calculation,
m = -v / u
-v = m . u
-v = (-3)(-10) cm
-v = 30 cm
v = -30 cm
Ans.) Image is located 30 cm in front of the mirror on the left.
Magnification m = -3 (real image)
Object-distance u = -10 cm (object on the left)
Calculation,
m = -v / u
-v = m . u
-v = (-3)(-10) cm
-v = 30 cm
v = -30 cm
Ans.) Image is located 30 cm in front of the mirror on the left.
duragpalsingh:
why magnification is -3
a concave mirror if it produces real image,the magnification will be negative.if it is a virtual image it will be positive.
how -3×-10= -30 ??
its actually -v = 30 thats why v = -30
Yes. I know it. But please mention sign conventions clearly.
users who are reading will get confused.
last three lines are not clear
is it in my answer?
no
@ imritz
Answered by
1
m = -3 (as it is a real image)
u = -10 (object distance is always negative)
v = ?
we know that,
m= -v/u
-3 = -v/-10
30 = -v
v = -30
thus the image is located 30 cms away from the mirror .it is on the same side real and inverted.
hope it helps!!!!
u = -10 (object distance is always negative)
v = ?
we know that,
m= -v/u
-3 = -v/-10
30 = -v
v = -30
thus the image is located 30 cms away from the mirror .it is on the same side real and inverted.
hope it helps!!!!
thx : )
thnx
: )
Similar questions