Question

a concave mirror produces three times magnified real image of an object placed at 10cm in front of it.where is the image located

Answer 1

hi
answer is .

Here,

Magnification, m = -4

Object distance, u = -10 cm

Image distance = v

Focal length = f

Now,

We know,

m = v/u

=> -4 = -v/10

=> v = 40 cm

Again,

1/f = 1/v + 1/u

=> 1/f = 1/40 – 1/10

=> f = -13.33

Since, the image is real the image is inverted.

Answer 2

magnification is -v/u=h'/h
u=-10cm
h'=3h
so -v/u= 3h/h
so -v/u=3
-v=3u
v= -3u
v=-3x-10
v = 30cm