A concave mirror produces three times magnified real image of an object placed at 10cm in front of it. Where is the image located?
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Answered by
1
Answer:
a concave mirror can produce both real images as well as a virtual image. But according to the given condition, the concave mirror is producing real and inverted image so
ACQ-
Height =h,height of image is 3h
m=h’/h...m=-3h/h
m=-3....u=-10cm
But we know that m=-v/u
-3=-v/-10... v=-30cm
Hence solved.
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Answered by
2
Answer:
m = -v/u for concave mirror.......(1)
given,
M = 3
u= 10cm
v= ?
substituting the above values in (1) we get ,
3 = -v/10
V = -30cm
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