a concave mirror produces three times magnified real image of object placed at 10 cm in front of it where is image located
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Concave
mirror can produce both real image as well as virtual image. But
according to the given condition the concave mirror is producing real
and inverted image soACQ-Height =h,height of image is 3hm=h’/hm=-3h/hm=-3u=-10cmBut we know that m=-v/u-3=-v/-10v=-30cmHence solved.
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Answer:
Given,m=-3(since image is real),u=-10 cm and v=?
Using the formula for magnification m=-v|u,we have
v=-mu=-(-3)(-10)=-30 cm
Therefore, the images is formed at a distance of 30 cm from the mirror in front of it.
Explanation:
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