In fig O is the centre of the circle . find angle ADB
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We know that
The angle subtended by an arc at the centre of the circle is twice the angle subtended the same arc at any point on the remaining part of the circle.
hence Angle ACB = 40
From the given figure
ADBC is a cyclic quadrilateral
Opposite angles of a cyclic quadrilateral are supplementary.
Hence
Angle ACB + Angle ADB = 180 degrees
=> Angle ADB = 180 - 40 = 140 degrees
I hope this answer helps you
The angle subtended by an arc at the centre of the circle is twice the angle subtended the same arc at any point on the remaining part of the circle.
hence Angle ACB = 40
From the given figure
ADBC is a cyclic quadrilateral
Opposite angles of a cyclic quadrilateral are supplementary.
Hence
Angle ACB + Angle ADB = 180 degrees
=> Angle ADB = 180 - 40 = 140 degrees
I hope this answer helps you
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6
The angle subtended by an arc at the centre of the circle is twice the angle subtended the same arc at any point on the remaining part of the circle.
hence Angle ACB = 40
From the given figure
ADBC is a cyclic quadrilateral
Opposite angles of a cyclic quadrilateral are supplementary
Hence
Angle ACB + Angle ADB = 180 degrees
=> Angle ADB = 180 - 40 = 140 degrees
I hope this answer helps you
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