Question

a concession stand sold 8 more pretzels than nachos at the last volleyball game. Pretzels cost 2 dollars and nachos cost 3 dollars. If the concession stand made 94 dollars, how many of each were sold?

Answer 1

Given:

A concession stands sold 8 more pretzels than nachos at the last volleyball game.

Pretzels cost 2 dollars and nachos cost 3 dollars.

If the concession stand made 94 dollars

To find:

How many of each were sold?

Solution:

Let's consider,

"P" → represents the no. of pretzels

"N" → represents the no. of nachos

The total amount that the concession stand made at the game = 94 dollars

The concession stand sold 8 more pretzels than nachos at the game, so we get the equation as:

P = N + 8

According to the question, we get

$2P + 3N = 94$

$\implies 2(N + 8) + 3N = 94$

$\implies 2N + 16 + 3N = 94$

$\implies 2N + 3N = 94 - 16$

$\implies 5N = 78$

$\implies \bold{N = \ \:15.6}$

∴ P = N + 8 = 15.6 + 8 = $ 23.6

Thus, each of them was sold at:

$\boxed{\bold{Pretzels \rightarrow \underline{\ \: 23.60}}}$

$\boxed{\bold{Nachos \rightarrow \underline{\ \: 15.60}}}$

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