Question

A conducintg circular loop having a redius of 5.0cm, is placed perpendicular to a magnetic field of 0.50 T. It is removed from the field in 0.50 s. Find the average emf produced In the loop during this time.

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

A conducintg circular loop having a redius of 5.0cm, is placed perpendicular to a magnetic field of 0.50 T. It is removed from the field in 0.50s. Find the average emf produced In the loop during this time.

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Radius of loop (r) = 5cm or ${\sf 5×10^{-2}m}$
• Magnetic Field (B) = 0.50T
• Time ${\sf (dt)}$ = 0.50s

$\large\underline{\underline{\sf To\:Find:}}$

• Average emf (e)

❏$\large{\boxed{\bf \blue{e=\dfrac{d \phi}{dt} }}}$

❏$\large{\boxed{\bf \blue{\phi=BA} }}$

A = Area = πr²

$\implies{\sf e=\dfrac{BA}{t}}$

$\implies{\sf e=\dfrac{0.50×(πr^2)}{0.50}}$

$\implies{\sf e=\dfrac{0.50×3.14×(5×10^{-2})^2}{0.50} }$

$\implies{\sf e = 3.14×25×10^{-4} }$

$\implies{\bf \red{EMF(e)=7.8×10^{-3}V}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Average emf produced In the loop during this time is ${\bf \red{7.8×10^{-3}V}}$