Question

a conducting ring of radius r is placed perpendicularly inside a time varying magnetic field given by B=Bi+ alpha•t. Bi and alpha are positive constant.Emf induced in the ring is​

Answer 1

induced emf = -d(phi)/dt = -d(B*A)/dt = -A dB/dt =-A*Bi*alpha
A =pi*r^2

Answer 2

Given :

B = Bi + αt

To find :

The Emf induced in the ring

Solution :

• Emf induced in the ring is given by the formula

       E = -(d∅/dt)

• E = -d(AB) / dt       [∅=AB]

• E = - A dB/dt

• E =  (πr²)× d(Bi+αt)

• E = πr² ×α
• E = πr²α

The emf induced in the ring is πr²α