Question

Area of square garden ABCD is 2025m^2. Inside the garden part of uniform width runs around it's boundary. Area of path is 518m^2 find the area of unshaded portion, perimeter of unshaded portion and width of park.

Answer 1

HEY MATE,

AREA OF SQUARE = S X S

2025 = S^2

45 M = SIDE

SO PERIMETER OF PARK = 45 X 4

= 180M

AREA OF UNSHADED REGION = AREA OF PARK - AREA OF SHADED REGION

= 2025-518

= 1507 M^2

SO THE AREA OF UNSHADED REGION = 1507M^2.

SO NOW,

AREA OF UNSHADED REGION = S X S

1507 = S^2

38.8 M (APPROX) = S

SO PERIMETER OF UNSHADED REGION = 4 X S

= 4 X 38.8

= 155.5 M

SO THE PERIMETER OF UNSHADED REGION = 155.5 M.

I HOPE THIS WILL HELP YOU...

PLS MARK AS BRAINLIEST.

Answer 2

Answer:

where is the width

Step-by-step explanation:

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