Question

A conducting rod of length 1 m and mass 1 kg is suspended by two vertical wires through its ends. An external magnetic
field of 2 T is applied perpendicular to rod and plane of arrangement. The current to be passed through the rod to make
tension zero is (g = 10 m/s2)

Answer 1

Answer:

Explanation:

magnetic force on rod = BIℓ

Weight of the rod = mg.

for no tension in the wire, BIℓ = mg

∴ I = (mg/Bℓ) = [(1 × 10)/(R × 1)]

I = 5A

Explanation:

Please Mark Me as Brainliest