A conducting wire of 50cm length and area of cross section 0.05mm2 has a resistance of 10Ω. Find its resistivity
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Answer:
10^(-6) Ohm Metre
Explanation:
Roh=RA/L
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Answer: ρ = 25 × 10⁻⁸ Ω⁻¹
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Explanation:
ρ = RA / L
↓ ↓ ↓ ↓
ρ = 10Ω × [0.05 × 10⁻⁶]m² × [50 × 10⁻²]m
ρ = 10 × 5 × 50 × 10⁻¹⁰
ρ = 2500 × 10⁻¹⁰
ρ = 25 × 10⁻⁸ Ω⁻¹
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