Question

a conducting wire of length -3k moving with velocity i+2j+3k in a magnetic field of i+3j+k . find the potential difference between two ends of a conducting wire?

Answer 1

Answer:

EMF induced across the ends of the rod is -3 Volts

Explanation:

As we know that the potential difference across the ends of current carrying wire is given by Faraday's law of electromagnetic induction

So it is given as

$EMF = (\vec v \times \vec B).\vec L$

now we have

$\vec v = \hat i + 2\hat j + 3\hat k$

$\vec L = - 3\hat k$

$\vec B = \hat i + 3\hat j + \hat k$

now by above formula we have

$EMF = (\hat i + 2\hat j + 3\hat k)\times (\hat i + 3\hat j + \hat k) .(-3\hat k)$

$EMF = (3\hat k - \hat j -2\hat k + 2\hat i + 3\hat j - 9\hat i).(-3\hat k)$

$EMF = -9 + 6 = -3 V$

#Learn

Topic : Faraday's Law

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