Question

a conductivity cell when filled with 0.01 M Lol has a resistance of 745ohm at 25 celesius when the same celll filled with aqueous solution of 0.05M Cacl2 solution the resistance was 874 ohm calculate conductivity of solutions and molar conductivity of solutions​

Answer 1

Answer:

Resistance of KCl solution, R = 85 ΩCell constant = K x R =1.29 ... When a certain conductivity cell was filled with 0.1 M KCl, it has a resistance of 85 Q at 25°C. When the same cell ... electrolyte, the resistance was 96 Ω. Calculate the molar conductivity of the ... (Specific conductivity of 0.1 M KCl = 1.29 x 10–2 ohm–1cm–1).