A conductivity of cell filled with 0.1M KCl gives at 25°C a resistance of 85.5 ohms. The conductivity of 0.1M KCl at 25°C is 0.01286 Ω⁻¹ cm⁻¹. The same cell filled with 0.005M HCl gives a resistance of 529 ohms. What is the molar conductivity of HCl solution at 25°C
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The formula of the cell constant will be = K * R
= 1.29 * 10^-2 * 85.5
= 1.1 cm^-1
Resistance = 947
K = cell constant/R = 1.1/9470
Concentration, C = 0.052 * mol/1000 cm^3
= 5.2 * 10^-5 ,mol cm ^-3
Molar conductance = K/C = 11/9470 * 5.2 * 10^-5 = 22.33
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Answer:
The formula of the cell constant will be = K * R
= 1.29 * 10^-2 * 85.5
= 1.1 cm^-1
Resistance = 947
K = cell constant/R = 1.1/9470
Concentration, C = 0.052 * mol/1000 cm^3
= 5.2 * 10^-5 ,mol cm ^-3
Molar conductance = K/C = 11/9470 * 5.2 * 10^-5 = 22.33
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