Question

A conductor carries a current of 300mA. The number of electrons passing through it in 1min are

about

a) 1.125 x 1017 b) 1.125 x 1020 c) 1.125 x 1023 d) 1.125 x 1025​

Answer 1

Answer:

ANSWER

Current, I=3mA=3×10

−3

A

Hence, charge passing per minute, Q=It=3×10

−3

×60=0.18C

And charge on one electron=e=1.6×10

−19

C

Hence, Number of electron=N=

e

Q

⟹N=

1.6×10

−19

0.18

⟹N≈10

18

Answer-(A)