a conductor has 1 coulomb charge how many are in electrons excess or short
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charge on one electron = -1.6×10^(-19) C
no. of electrons = \frac{2.4*10^{-18}}{1.6*10^{-19}} = \frac{24}{1.6} =15
Since the charge on the conductor is positive, the conductor is 15 electrons short.
________hope it helps you...
no. of electrons = \frac{2.4*10^{-18}}{1.6*10^{-19}} = \frac{24}{1.6} =15
Since the charge on the conductor is positive, the conductor is 15 electrons short.
________hope it helps you...
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