Question

A conductor of axial length 30 cms carries a current of 100 a and lies at right angle to a magnetic field of strength 0.4 tesla. What is the force exerted on it ?

Answer 1

Hello mate,

◆ Answer-

F = 12 N

◆ Explaination-

# Given-

I = 100 A

l = 30 cm = 0.3 m

B = 0.4 T

θ = 90°

# Solution-

Force acting on conductor in magnetic field is given by-

F = IlBsinθ

Substitute values-

F = 100 × 0.3 × 0.4 × sin90

F = 12 N

Therefore, force acting on current carrying conductor in given magnetic field is 12 N.

Hope it helps...