Prove that a cone with least curved surface area and given volume has radius =
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Let r and h be the radius and height of the cone respectively.
Volume V=13πr2h
=πk3(constant) r2h=k or h=kr2------(1)
Surface S=πrl=πr(h2+r2−−−−−−√)
h=kr2from (1)
S=πrk2r4+r2−−−−−−−√
=πrk2+r6−−−−−√r4
=πk2+r6−−−−−√r
Step 2:
dSdr=π[6r52r6+k2√×r−r6+k−−−−√.1r2]
=3r6−(r6+k2)r2(r6+k2−−−−−√)
=(2r6+k2)r2(r6+k2−−−−−√)
=k2=2r6
dSdr=0
Step 3:
dSdr changes sign from -ve to +ve as r increases through the point k2=2r6
⇒S is the least at this point.
From (1) k2=h2r4
h2r4=2r6
h2=2r2
h=2r2−−−√
h=r2–√
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