Question

A conductor of length 50 cm carrying a current of 5 A is placed perpendicular to a magnetic field of induction 2 x 10-3 Tesla, then the force on the conductor is

Answer 1

Answer:

Force on the conductor = ILB = 5 × 50 × 10-2 × 2 × 10-3 = – 5 × 10-3

Explanation:

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