Question

A cone has a diameter of 10 inches. If its height is twice its radius, about what is the volume of the cone in cubic inches?

Answer 1

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Answer 2

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Diameter of the cone = 10 inches
Radius = D/2
= 10/2
=5 inches
Height of the cone =2x Radius
= 2 x 5
= 10 inches
$volume \: = \frac{\pi \: r {}^{2} h}{3} \\ = \frac{22 \times 5{}^{2} \times 10 }{7 \times 3} \\ = \frac{220 \times 25}{21} \\ = \frac{5500}{21} \\ = 261.90 \: inches$
So volume of the cone is 261.90 inches

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