Question

In a rhombus ABCD, angle ACB=60. Find angle BAC angle DCA angle ADC

Answer 1

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If ∠DAB=∠DCB=60°

This means that DAB  and DCB are equilateral

so ∠ADB=60°

∠POB=θP=(√3/2 cosθ,√3/2sinθ)

A=(0,3–√)B=(1,0)C=(0,−3–√)D=(−1,0)

(Let O the center of the circle

and the radius of the circle is r=AOsin60°

=√3/2 and the distance

AO=√3

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