Question

a cone is cut into three parts by planes through the points of trisection of its aptitude and parallel to the base. prove that the volumes of the parts are in the ratio of 1:7:19.​

Answer 1

Answer:

Let the radii of three cones from top be r1,r2 and r3 respectively. Let the height of given cone be 3 h. so, the height of cone ADE = 2 h and height of cone ABC =h Volume of frustum DEGF Hence, required ratio = 1 : 7 : 19.

Step-by-step explanation:

i this this answer is right