Question

A cone is having its base radius 12 cm and height 20 cm. If the top of this
cone is cut into form of a small cone of base radius 3 cm is removed, then
the remaining part of the solid cone become a frustum. Calculate the
volume of the frustum.
Radius 3 cm
Height 20 cm
* Radius 12 cm​

Answer 1

Volume of the frustum will be 2970 $cm^3$

Step-by-step explanation:

$\textrm{Volume of cone is given as}V=\frac{1}{3} \pi r^2h$

$\textrm{Now the volume of cone }=\frac{1}{3} \times\frac{22}{7} \times12^{2} \times20$

$= 3017.14cm^3$

$\textrm{Now the height of smaller cone will be calculated as}$

$\frac{20}{12} =\frac{x}{3}$

$\textrm{after solving this we can get x} =5cm$

$\textrm {So the volume of smaller cone will be}=\frac{1}{3} \times\frac{22}{7} \times3^{2} \times5$

$=47.14 cm^3$

$\textrm {Now volume of frustum of cone is given by} \\=\textrm {Volume of bigger cone -Volume of smaller cone}\\=3017.14 - 47.14\\=\bold{2970 cm^3}$

Answer 2

Answer:2970cmcube

Step-by-step explanation: