Question

A cone lies in a uniform electric field E as shown in the figure. The electric flux entering through the cone is ?

Answer 1

hope it helped you...

Answer 2

The cross-section of the plane in which the electric field enters is a triangle.

It is a triangle with a base length of 2R and a height of h and is normal to the electric field.

Area of triangle $A = \frac{1}{2}\times base\times height= \frac{1}{2}\times 2R\times h$

We know, Electric flux entering the cone

$= E.A\\=E\times A$ [$\because$plane is normal to the electric field so the area vector of plane is parallel to electric field]

Electric flux entering the cone$=ERH$

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