Question

In a parallelogram ABCD Angle A is double of angle B.Find all the angles of the parallelogram

Answer 1

angle A is x so angle B is 2x
so, angle C is C=A and angle D=B

Answer 2

Answer:

Angles of parallelogram are

∠A=∠C=120°

∠B=∠D=60°

Step-by-step explanation:

Given parallelogram ABCD in which ∠A is double of ∠B.

We have to find the measure of all angles of parallelogram.

As ∠A is double of ∠B i.e

∠A=2∠B let ∠B is of measure x.

⇒ ∠A=2x=∠C

and ∠B=x=∠D

Also the opposite angles of parallelogram are of equal measure.

∠A=∠C and ∠B=∠D

Sum of all angles of quadrilateral is 360° i.e

∠A+∠B+∠C+∠D=360°

2x+x+2x+x=360°

⇒ 6x=360°

⇒ x=60°

Hence, angles of parallelogram are

∠A=∠C=2x=2(60)=120°

∠B=∠D=x=60°