A cone of height 8m has a curved surface area 188.4 square metres. find its volume
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27
Given, height of cone, h = 8 m
Let r be radius and l be slant height of cone,
Given, curved surface are of cone = 188.4 m2
⇒ πrl = 188.4
On squaring both sides, we get
r4 + 100 r2-36r2 -3600 = 0
r2(r2 + 100) -36 (r2 + 100) = 0
(r2-36)(r2+100) = 0
⇒ r2 = 36, -100
r2 ≠ -100
⇒ r2 = 36
or r = 6 cm
Hence radius is 6 cm.
Let r be radius and l be slant height of cone,
Given, curved surface are of cone = 188.4 m2
⇒ πrl = 188.4
On squaring both sides, we get
r4 + 100 r2-36r2 -3600 = 0
r2(r2 + 100) -36 (r2 + 100) = 0
(r2-36)(r2+100) = 0
⇒ r2 = 36, -100
r2 ≠ -100
⇒ r2 = 36
or r = 6 cm
Hence radius is 6 cm.
Answered by
8
Given:
1. height of a cone is h
so that,
h=8m
let assume r is the radius and L is the tilt height or length of a cone.
2. curved surface are of cone is A,
so that ,
A= 188.4 square meters
r=root(A²/(pi*(pi*h²+2A)))
r=root(188.4²/(pi*(pi*8²+2(188.4)))
r=4.42 m
volume of a cone can be given as,
V=pi*r²*h/3
V=pi*(4.42)²*8/3
V=163.66 cubic metres
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