A cone of hight 8.4 cm and radius of base 2.1 cm us melted into sphere.The diameter of sphere will be
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Solution :
Given ,height of a cone = 8.4 cm
Radius of the base of cone = 2.1 cm
Volume of a cone =13πr2h=13×π×(2.1)2×8.4
=13×π×2.1×2.1×8.4=π×4.41×2.8cm3
Since, cone is melted and recast into a sphere.
Let the radius of a sphere be R.
Thlen, volume of a sphere = Volume of a cone
⇒ 43πr3=π×4.41×2.8⇒r3=4.41×2.8×34
⇒ r3=4.41×0.7×3
⇒ r3=4.41×2.1
∴ r=2.1
Hence , the radius of the sphere is 2.1 cm.
since the radius of the sphere is 2.1 cm
diameter = 2.1×2
= 4.2
therefore the diameter of the sphere is 4.2 cm.
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Radius of the base = the radius of the sphere
Diameter = 2 *2.1cm = 4.2cm
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