Question

a cone of radius 10 cm It is cut into two parts of a plane through the midpoint of a vertical Axis parallel to the base find the ratio of their volumes of the smallest cone and frustum of the cone ​

Answer 1

Answer:

1:7 volume of frustrum

Step-by-step explanation:

let the height of the given cone=h cm

on dividing it in to two parts we get

(1)frustum of the cone with radius R=10 cm

and radius r=5cm and height=(h/2)cm

(2)A samller cone of radius r=5cm and height =(h/2)cm

Therefore Ratio of the volumes=volume of the

smaller cone÷volume of the frustum of the cone

1÷3×πr2×(h/2)÷1÷3π(h÷2)[R2+r2+Rr]

Now pu the wole values in this equation

(5×5)÷[10^2+5^2+10×5]

25÷175=1÷7

1:7 is your Answer

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