Question

A cone of radius 10cm is divided into two parts by a plane parallel to its base through the midpoint of its height. Compare the volume of the two parts.
Pls answer fast
✌50 points✌​

Answer 1

Answer:

Hope this helps you...

Answer 2

Hi Mate,

Let the height of the cone = h cm

on dividing it in two parts, we get,

(i) Frustum if the cone with radius R = 10cm and radius r = 5cm and height = (h/2) cm

(ii) a smaller cone of radius r = 5cm and height = (h/2)

$Ratio of the Volumes = \frac{volume \: of \: the \: smaller \: cone}{volume \: of \: the \: frustum \: of \: the \: cone}$

$= \: \frac{( \frac{1}{3} )\pi {r}^{2} (\frac{h}{2}) }{ \frac{1}{3}( \frac{h}{2})( {r}^{2} + \: {r}^{2} + \: rr)}$

$= \frac{5 \: \times \: 5}{ {10}^{2} + \: {5}^{2} + \: 10 \: \times \: 5}$

$\frac{25}{175} = \frac{1}{7}$

= volume of the smaller cone : volume of frustum of the cone

= 1 : 7

Hope this answer will help you...(◔‿◔)