Question

a cone of radius 12cm and hight 20cm it cut from the top 3cm and value of parallel to the base the remaining part becomes a frustom of cone. find the ratio of volume of the cone removed and volume of the frustom of the cone​

Answer 1

Answer:

63

Step-by-step explanation:

h1 - height of the bigger cone = 20 cm

h2 - height of the smaller cone = x

r1 - radius of the bigger cone = 12 cm

r2 - radius of the smaller cone = 3 cm

h1/h2 = r1/r2 => 20/x = 12/3

x= 5cm

The volume of the bigger cone = 1/3 × π(r1)²h1

= (22/7) × (12)² × 20

= 3014.4 cm³

The volume of cone cut off = 1/3 × π(r2)²h2

= (22/7) × (3)² × 5

= 47.1 cm³

The volume of the frustum = 3014.4 - 47.1

= 2967.3 cm³

Ratio = Volume of the frustum/Volume of the cone removed

= 2967.3/47.1 = 63

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