Question

a confectioner had some boxes. he bought 50 more boxes and after two days half of these boxes were used and 40 boxes were left. find the number of boxes he had in the beginning. math question

Answer 1

let the no of boxes he had be x
new no of boxes = x+50
BTQ
(x+50)/2=40
x+50 = 80
x = 80 -50
x = 30
:. the confectioner in the beginning had 30 boxes

Answer 2

HEYA HERE IS UR ANSWER............................
             
                a confectioner had some boxes.
                     Let the boxes = x
 again he bought 50 more boxes = x+50----------------------(1)

  ==>after 2 days half of these boxes were used 
                                                                              =>x+50-40
                                                                              =>x+10-------------(2)
           from equation 1 and 2 
                                        
                       x+50=x+10
       
                       x= x+10-50
 
                     =>x=10
               ' 
 ' 
' 
there fore the boxes in the beginning are 10

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