Question

A conference hall is 14 m long, 8 m wide and 4 m high. There are
foor in it. The door measures 1 m by 2 m and each window measures 1 m by 1.5m.
a) How many litres are needed to paint all the walls of the hall if is enough for covering 18 m-?
b)What will be the cost of painting the hall if 1 litre costs ₹ 2252?

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Answer 1

Step-by-step explanation:

(a)

We have,

Length = 14 m.

Breadth = 8 m.

Height = 4 m.

(i) Area of 4 walls of the hall = 2h(l + b)

                                             = 2 * 4(14 + 8)

                                             = 176 m²

(ii)

Area of 1 door = 2 m².

Area of 1 window = 1.5 m²

∴ Area of 4 windows = 4 * 1.5

                                  = 6 m²

∴ Area of four walls to be painted = [176 - (2 + 6)]

                                                       = 176 - 8

                                                       = 168 m²

Given that one litre is enough for covering 18 m².

Then, cost of painting 168 m² = (168/18)

                                                = 28/3

                                         = 9(1/3) litres.

(b)

1 litre = 225

9(1/3) litres = ?

⇒ (225 * 28)/3

⇒ 6300/3

⇒ 2100.

Therefore, cost of painting is 2100.

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