Question

A conference hall is 14 m long, 8 m wide and 4 m high. There are four windows and one door in it. The door measures 1 m by 2 m and each window measures I m-by 15 m. (a) How many litres are needed to paint all the walls of the hall if one litre is enough for covering 18 m2? b) What will be the cost of painting the hall if 1 litre costs 225? Answer it fast

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

(a)

We have,

Length = 14 m.

Breadth = 8 m.

Height = 4 m.

(i) Area of 4 walls of the hall = 2h(l + b)

                                              = 2 * 4(14 + 8)

                                              = 176 m²

(ii)

Area of 1 door = 2 m².

Area of 1 window = 1.5 m²

∴ Area of 4 windows = 4 * 1.5

                                   = 6 m²

∴ Area of four walls to be painted = [176 - (2 + 6)]

                                                        = 176 - 8

                                                        = 168 m²

Given that one litre is enough for covering 18 m².

Then, cost of painting 168 m² = (168/18)

                                                 = 28/3

                                          = 9(1/3) litres.

(b)

1 litre = 225

9(1/3) litres = ?

⇒ (225 * 28)/3

⇒ 6300/3

⇒ 2100.

Therefore, cost of painting is 2100.

Hope it helps!