If an electric iron of 1500 W is used for 45 min every day, find the electric energy consumed in the month of march
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p=1500w
t=45min=45÷60 hour
Kwh=?
days in march=31days. units per days=1500x45÷60
=150x45÷6
=50x45÷2
=25x45
=1125
total energy consumed=31x1125
=34875 units
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