A conference hall is 30m long and 20m bread and 7m high it was 6 windows of size 2m×3m find the area of the walls of this house?
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Answered by
1
Curved Surface area of room (cuboid)=
=2×(bh+hl)
=2×(20×7+ 7×30)
=2×(140+210)
=2×350
=700 m^2
Area of six windows
=6×(area of rectangle)
=6×l×n
=6×2×3
=36m^2
Area of walls= curved surafacr Area of room - area of 6 windows
=700 - 36
=664 m^2
=2×(bh+hl)
=2×(20×7+ 7×30)
=2×(140+210)
=2×350
=700 m^2
Area of six windows
=6×(area of rectangle)
=6×l×n
=6×2×3
=36m^2
Area of walls= curved surafacr Area of room - area of 6 windows
=700 - 36
=664 m^2
Answered by
0
Lateral surface area of the hall=2(l+b)h
=2(30+20)×7
=(2×50)×7
100×7m^2
700m^2
Area of 6 Windows =(2m×3m)×6
6m^2 ×6=36m^2
Area of the walls = Lateral surface area of the hall- Area of 6 Windows
= 700-36
=664m^2
=2(30+20)×7
=(2×50)×7
100×7m^2
700m^2
Area of 6 Windows =(2m×3m)×6
6m^2 ×6=36m^2
Area of the walls = Lateral surface area of the hall- Area of 6 Windows
= 700-36
=664m^2
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