Question

If 3is a zeroes of the polynomial p(x) =kx²-2(k-1)x-1,then value of k is...

Answer 1

put x=3 in given eqn.
$k {3}^{2} - 2(k - 1)3 - 1 = 0 \\ 9 {x}^{2} - 2k + 2 \times 2$

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .