a conical heap is formed when a farmer pours food grains on ground. the slant height of heap is 35 cm.the circumference of the base is 132 cm.what amount of tarpaulin is needed to cover the grains?the farmer goes to an orphanage and gives half of the food grain for the children living there. how much he donated
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Given slant height (l) = 35 cm
circumference = 2πr = 132
πr = 66 cm
curved surface area of the heap = πrl =66 × 35 = 2310 sq.cm
r = 66 × 7/22
r = 21
height of the heap =√ 35² - 21²
height of the heap = 28
volume of heap = πr²h
volume of the heap = 66×21×28 = 38808 cm³
the farmer donated = 19404cm³ of grains
circumference = 2πr = 132
πr = 66 cm
curved surface area of the heap = πrl =66 × 35 = 2310 sq.cm
r = 66 × 7/22
r = 21
height of the heap =√ 35² - 21²
height of the heap = 28
volume of heap = πr²h
volume of the heap = 66×21×28 = 38808 cm³
the farmer donated = 19404cm³ of grains
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