A conical heap of rice having diameter 24m and heigt 3.5m how much canvas would we used to cover the heap
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Since, heap is in the form of a cone.
where, d=24m, r=12m and h=3.5m
l (slant height)= √h2+r2
=) √ (3.5)2+ (12)2
=) √12.25+144
=) √156.25
=)12.5 cm = slant height
Now, S.A of heap =πrl
=) 22/7× 12× 12.5
=) 471.42 cm2
Hence, 471.42 cm2 of canvas would be needed to cover the heap.
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where, d=24m, r=12m and h=3.5m
l (slant height)= √h2+r2
=) √ (3.5)2+ (12)2
=) √12.25+144
=) √156.25
=)12.5 cm = slant height
Now, S.A of heap =πrl
=) 22/7× 12× 12.5
=) 471.42 cm2
Hence, 471.42 cm2 of canvas would be needed to cover the heap.
Plzzz mark as Brainliest
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