A current of 5ma flows in a resistance less choke from a 200v alternating source. the energy consumed in the choke is
Answers
Answered by
0
v=200v
I = 5ma
=5/1000
=0.005a
v=ir
200=0.005*r
40000=r
I = 5ma
=5/1000
=0.005a
v=ir
200=0.005*r
40000=r
Answered by
0
Answer:
choke is resistance less so,energy consumed is 0j
Similar questions