a conical tent 10cm high and the radius of its base is24 cm .....find slant height of tent and cost of canvas required to make the tent it cost of 1msq canvas is 70.
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☺☺ HERE IS IS YOUR ANSWER ☺☺
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Height of cone = 10cm
Radius of cone = 24cm
slant height = √(h^2+r^2)
=√(10^2+24^2)
=√(100+576)
=√676
=26 cm
CSA of cone = πrl
=22/7 × 24 × 26
=13728/7
=1961.14cm^2
1cm^2 = 0.0001 m^2
1961.14 cm^2 =0.196114m^2
1m^2 = 70
0.196114m^2 = 0.196114 × 70
=13.73
_________________________________
☺HOPE IT HELPS YOU☺
THANKS..
___________________________________
Height of cone = 10cm
Radius of cone = 24cm
slant height = √(h^2+r^2)
=√(10^2+24^2)
=√(100+576)
=√676
=26 cm
CSA of cone = πrl
=22/7 × 24 × 26
=13728/7
=1961.14cm^2
1cm^2 = 0.0001 m^2
1961.14 cm^2 =0.196114m^2
1m^2 = 70
0.196114m^2 = 0.196114 × 70
=13.73
_________________________________
☺HOPE IT HELPS YOU☺
THANKS..
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