Question

a conical tent in the shape of cylinder shape surmounted by cone of common diameter 56m​

Answer 1

Correct Question :

• Diameter of Cylinder(d) = 56 m

• Radius of Cylinder(r) = 56/2 m = 28 m [Hence, Radius is the half of the Diameter].

• Height of Cylindrical part = 6m

Now,

⇒ C.S.A of Cylinder = 2 x π x r x h.

→ C.S.A = 2 x 22/7 x 28 x 6

→ C.S.A = 2 x 22 x 4 x 6

→ C.S.A = 1056 m^2

Again,

Cylinder is summounted by Cone.

• Radius of Cone = Radius of Cylinder = 28 m

• Height of Cone = Total height of tent-Height of Cylinder = (27-6) m = 21 m

Now,

We are required to find out Slant Height of Cone, For which there is a Formula,

$\huge\boxed{ }$   l^2 = r^2+h^2

$\huge\boxed{ }$   l^2 = 28x28 + 21x21

$\huge\boxed{ }$   l^2 = (784+441) m^2

$\huge\boxed{ }$   l^2 = 1225 m^2

$\huge\boxed{ }$   l = Root 1225 m^2

$\huge\boxed{ }$   l = 35 m.

Now,

⇒ C.S.A of Cone = π x r x l

↔ C.S.A = 22/7 x 28 x 35

↔ C.S.A = 22 x 4 x 35

↔ C.S.A = 3080 m^2

Now,

• Total Area covered by Canvas = C.S.A of Cylinder + C.S.A of Cone

→→ Total area = (1056+3080) m^2

→→ Total area = 4136 m^2

$\huge\boxed{Hope*IT*helps*U}$