A conical tent is 10m high and the radius of its base is 24m if the cost of 1m2 canvas is rs.70 then find 1.slant height of the tent 2.cost of the canvas to make the tent
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Right circular cone:
If a right angled triangle is revolved about one of the two sides forming a right angle keeping the other side fixed in position then the solid so obtained by segments is called right circular cone.
Slant height:
The length of the line segment joining the vertex to any point on a circular edge of the base is called the slant height of the cone.
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Given:
Radius of the base (r) = 24 mHeight of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know thatl²= r²+h² l = √h²+r² l = √10²+ 24²l = √100 + 576l = 26 m
Slant height (l)= 26 m
(ii) Canvas required to make the conical tent = Curved surface of the cone
Cost of 1 m2 canvas = ₹70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost of canvas = ₹ 13728/7 × 70 = ₹137280
Hence, required cost of the Canvas is ₹137280
=========================================================
Hope this will help you....
If a right angled triangle is revolved about one of the two sides forming a right angle keeping the other side fixed in position then the solid so obtained by segments is called right circular cone.
Slant height:
The length of the line segment joining the vertex to any point on a circular edge of the base is called the slant height of the cone.
----------------------------------------------------------------------------------------------------
Given:
Radius of the base (r) = 24 mHeight of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know thatl²= r²+h² l = √h²+r² l = √10²+ 24²l = √100 + 576l = 26 m
Slant height (l)= 26 m
(ii) Canvas required to make the conical tent = Curved surface of the cone
Cost of 1 m2 canvas = ₹70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost of canvas = ₹ 13728/7 × 70 = ₹137280
Hence, required cost of the Canvas is ₹137280
=========================================================
Hope this will help you....
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