Question

A conical tent is 12m high and the redius of the base is 16m.Find the slant hight of the tent.
​

Answer 1

ANSWER:

• slant height (l) of cone = 20cm

GIVEN:

• Height of conical tent = 12 m
• Radius of base = 16 m

TO FIND:

• Slant height of conical tent (l)

SOLUTION:

Formula

$\implies \: l \: = \sqrt{r {}^{2} + h {}^{2} }$

Where l = slant height r = radius of cone

l = slant height r = radius of cone h = height of cone

Putting the value in formula we get;

$\implies \: l \: = \sqrt{(16) {}^{2} + (12) {}^{2} } \\ \implies \: l = \sqrt{256 + 144} \\ \implies \: l \: = \sqrt{400} \\ \implies \: l = 20 \: cm$

So slant height (l) of cone = 20cm

NOTE:

some important formulas

• Volume of cone =:
• $\frac{1}{3} \pi \: r {}^{2} h$
• Lateral surface area of cone:
• $\pi \: rl$
• Total surface area of cone
• $\pi \: r(l + r)$
• Where r = radius. l = slant height. π = 22/7 or 3.14...
• h = height of cone

Answer 2

Answer:

Given:

A conical tent is 12m high and the redius of the base is 16m.

To Find:

We need to find the slant hight of the tent.

Solution:

We know that,

$l = \sqrt{ {r}^{2} + {h}^{2} }$

Here, l is the slant height , r = radius of the cone and h = height of the cone.

Substituting the given values, we get

$l = \sqrt{ {16}^{2} + {12}^{2} }$

$= > l = \sqrt{256 + 144}$

$= > l = \sqrt{400}$

$= > l = 20cm$

Therefore, slant height of the cone is 20cm.