Question

a conical tomb is 24 m high and the base diameter is 14 m. find its curved suface area
please tell me fast!​

Answer 1

$\color{deeppink} \bold{Given,} \\ \\ \sf \: Height \:=\:24\:m\:\:\:|\:\:\:Diameter\:=\:14\:m \\ \\ \color{lightgreen} \bold{Solution} \\ \\ \sf \: Radius \: = \: \frac{14}{2} \: = \: 7 \: m \\ \\ \sf \: Slant \: height \: = \: \sqrt{ {r}^{2} \: + \: {h}^{2} } \\ \\ \sf \: Slant \: height \: = \: \sqrt{ {7}^{2} \: + \: {24}^{2} } \\ \\ \sf \: Slant \: height \: = \: \sqrt{49 \: + \:576} \\ \\ \sf \: Slant \: height \: = \: \sqrt{625} \\ \\ \sf \: \color{gold}Slant \: height \:(l) = \:25 \: m \\ \\ \sf \: \boxed{ \sf \: Curved \: Surface \: Area_{(cone)} \: = \: \pi \times r \times l} \\ \\ \sf \: Curved \: Surface \: Area \: = \: \frac{22}{7} \times 7 \times 25 \\ \\ \sf \: Curved \: Surface \: Area \: = \:550 \: {m}^{2}$

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Extra Formulas

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²