a constant force 2i+3j+4k n produces a displacement of ( 2i+3j+4k)m. what is the work done
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Answer:
Work done by the body is 29 Nm
Explanation:
As we know that work(W) done by a body is the dot product of force(F) and displacement(d)
W=F.d
Therefore answer is 29 Nm
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