Physics, asked by anjlakhan1234, 5 months ago

a constant force 2i+3j+4k n produces a displacement of ( 2i+3j+4k)m. what is the work done​

Answers

Answered by akashtonger9299
5
Hope it helps you plz mark as brilliant answer
Attachments:
Answered by brainly7901
2

Answer:

Work done by the body is 29 Nm

Explanation:

As we know that work(W) done by a body is the dot product of force(F) and displacement(d)

W=F.d

Therefore answer is 29 Nm

Attachments:
Similar questions