Question

a constant force 2i+3j+4k n produces a displacement of ( 2i+3j+4k)m. what is the work done​

Answer 1

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Answer 2

Answer:

Work done by the body is 29 Nm

Explanation:

As we know that work(W) done by a body is the dot product of force(F) and displacement(d)

W=F.d

Therefore answer is 29 Nm