Question

A constant force act on object of mass 6 kg for a duration of 1.5 sec. it increase the object velocity 9 m/s to 15 m/s .find the magnitude of force . the force was applied for a duration of 4 sec find final velocity

Answer 1

mass of object=6kg
time=1.5 sec
initial velocity =9m/s
final velocity = 15m/s

$f = \frac{m(v - u)}{t} \\ f =\frac{6 \times (15 - 9) \times 10}{15}$
$f = \frac{6 \times 6 \times 10}{15} \\ f = 24n$
24N
$f = \frac{mv - mu}{t} \\ 24= \frac{6v - 54}{4} \\ 24 \times 4 = 6v - 54 \\ 96 + 54 = 6v \\ 150 = 6v \\ v = 25$
25m/s