Question

A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m s–1 to 3.5 m s–1 in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?
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Answer 1

Answer:

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v = u + at

∴ a = (v - u) / t

= (3.5 - 2) / 25 = 0.06 ms-2

As per Newton’s second law of motion, force is given as:

F = ma

= 3 × 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

Answer 2

Answer:

Explanation:

Hey mate!!

Mass (m) = 3 kg

Initial velocity (u) = 2m/s

Final velocity (v) = 3.5 m/s

Time (t) = 25s

v = u + at

3.5 = 2 +a(25)

25a = 1.5

a = 0.06 m/s²

F = ma

F = 3 × 0.06

F = 0.18 N

Direction of force will be is toward the direction of motion.