Question

a constant force acting on a body of mass 3 kg and changes its speed from 2 metre per second to 3.5 M per second in 25 seconds that the direction of motion remain unchanged what is magnitude and direction of force

Answer 1

Hii bro
here u can see
the mass m=3kg
and speed is u=2m/s and v=3.5m/s
also the time is 25 secs

so, we know that

F= ma and

a= v-u/t

therefore,

a=3.5-2/25 =0.06

F= 3×0.06
=0.18 N

Answer 2

==============ⓢⓦⓘⓖⓨ

$\bold\red{hello...frd\:swigy\:here}$

==============ⓢⓦⓘⓖⓨ

ANSWER:-

0.18 N; in the direction of motion of the body

______________________❤❤

EXPLANATION:--

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v = u + at

=> a =( v - u)/t

= (3.5 - 2)/ 25

= 1.5/ 25

= 0.06 m/s^2

As per Newton’s second law of motion, force is given as:

F = ma = 3 × 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

I hope, this will help you

=======================

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________