Question

A constant force acting on a body of mass 3 kilograms changes its speed from to metre per second to 3.5 m per second in 25 second is in the direction of the motion of the body what is the magnitude and direction of the phone

Answer 1

$\huge\textbf{ANSWER}$
$<b>$
$\huge\mathfrak{Given}$

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration

(a) produced in the body can be calculated as:

v = u + at

$∴ a = \frac{(v - u)}{t}$

=>(3.5 - 2)/25

=>a = 0.06s^- 2

AS WE KNOW THAT

$\textbf{F = ma}$

= 3 × 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

$\huge\mathbb{THANKS}$

Have a colossal day ahead

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Answer 2

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ANSWER:-

0.18 N; in the direction of motion of the body

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EXPLANATION:--

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v = u + at

=> a =( v - u)/t

= (3.5 - 2)/ 25

= 1.5/ 25

= 0.06 m/s^2

As per Newton’s second law of motion, force is given as:

F = ma = 3 × 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

I hope, this will help you

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