Question

A constant force acting on a body of mass 3kg changes its speed from 2 metre per second to 3.5 metre per second in 25 second in the direction of motion of body what is the magnitude and direction of the force

Answer 1

Answer:

direction of motion of body and force is the same

F = 0.18 N

Explanation:

acceleration = change in velocity / time taken

= (3.5-2.0)/25

=1.5/25

=0.06m/s^2

F = mass × acceleration

= 3 × 0.06

= 0.18 N

Answer 2

$\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}$

• Mass (m) = 3kg
• Initial velocity (u) = 2 m/s
• Final velocity (v) = 3.5 m/s
• Time (t) = 25 s

As we know that

$\large \sf{F \: = \: ma}$

And also the acceleration is$\bf{a \: = \: \dfrac{v \: - \: u}{t}}$

So,

$\Large{\boxed{\sf{F \: = \: m (\dfrac{v \: - \: u}{t})}}}$

Put Values

⇒F = 3(3.5 - 2)/25

⇒F = 3(1.5)/25

⇒F = 4.5/25

⇒ F = 0.18 N

∴ Force is 0.18 N